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100-20h=-h^2
We move all terms to the left:
100-20h-(-h^2)=0
We get rid of parentheses
h^2-20h+100=0
a = 1; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$h=\frac{-b}{2a}=\frac{20}{2}=10$
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